How do I prove that these are the vertices of an isosceles triangle: (-3,0), (0,4), (3,0)?

Nov 14, 2015

Just determine the three sides.

Explanation:

$A = \left(- 3 , 0\right)$ on x axis

$B = \left(0 , 4\right)$ on y axis

$C = \left(3 , 0\right)$ on x axis

$A C = 6$

$A {B}^{2} = {3}^{2} + {4}^{2}$

$B {C}^{2} = {3}^{2} + {4}^{2}$

$A B = B C = 5$