How do I prove the identity of (sin^2Theta+2cosTheta-1)/(sin^2Theta+3cosTheta-3)=(cos^2Theta+cosTheta)/(-sin^2Theta) ?
(sin^2Theta+2cosTheta-1)/(sin^2Theta+3cosTheta-3)=(cos^2Theta+cosTheta)/(-sin^2Theta)
2 Answers
Please see below.
Explanation:
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Turn everything to cosines and grind out the algebra.