How do I prove this trigonometric identity?

cos^2beta/(1-sinbeta)=1+sinbetacos2β1sinβ=1+sinβ

1 Answer
Apr 28, 2018

cos^2beta/(1-sinbeta)=1+sinbetacos2β1sinβ=1+sinβ

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Multiply and divide by 1+sinbeta1+sinβ

=>(cos^2beta(1+sinbeta))/((1-sinbeta)(1+sinbeta))cos2β(1+sinβ)(1sinβ)(1+sinβ)

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=>(cos^2beta(1+sinbeta))/(1-sin^2beta)cos2β(1+sinβ)1sin2β

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=>(cancelcos^2beta(1+sinbeta))/cancel(cos^2beta
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->1+sinbeta