How do I set up the denominator after factoring for this integral? basically, how would you factor the bottom.

Question

#int_ ^ (1/(1-x^2))dx#

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Answer 1 · 2018-03-14T03:34:47

#1-x^2 = (1+x)(1-x)#

Factoring: #1-x^2 = (1+x)(1-x)#

Post an update if you have trouble with the integral. You only asked for factoring the denominator. Hope this helps!