How do I simplify this expression?

Question

#x^2-4x+4#/
#3x-6#

922 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-21T06:42:46

#(x-2)/3#

I'm guessing it is #[x^2-4x+4]/[3x-6]#

factorise

#[(x-2)(x-2)]/[3(x-2)]#

#(x-2)# is in the numerator and denominator so cancel them

#(x-2)/3#

Answer 2 · 2018-05-21T08:57:11

#(x - 2)/3#

From Your Question, I think it is #(x^2 - 4x + 4)/(3x - 6)#

So, We have,

#(x^2 - 4x + 4)/(3x - 6) = ((x)^2 - 2 * x * 2 + (2)^2)/(3(x - 2))#

#= (x -2)^2/(3(x - 2))# [As #(a - b)^2 = a^2 - 2ab + b^2#]

# = ((x - 2)cancel((x - 2)))/(3cancel((x - 2))) = (x - 2)/3#

We should assume #x - 2 != 0# Or else the expression would be undefined.

Hope this helps.