How do I solve #1/2z + 5 = 11# algebraically?

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I kinda understand but can someone help

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Answer 1 · 2018-05-16T20:34:21

#z=12#

#1/2z+5=11" "(-5 # from both sides)

#1/2z+5-5=11-5#

#1/2z=6" "xx2# on both sides (or #div 1/2#) "which is the same"

#z=12#