How do I solve 2(sin x-cos x)=3(sin x+cos x)2(sinxcosx)=3(sinx+cosx) ?

1 Answer
Jul 3, 2018

x=1.76,4.91x=1.76,4.91

Explanation:

2(sinx-cosx)=3(sinx+cosx)2(sinxcosx)=3(sinx+cosx)

2sinx-2cosx=3sinx+3cosx2sinx2cosx=3sinx+3cosx

-5cosx=sinx5cosx=sinx

tanx=-5tanx=5

If in the region of 00 and 2pi2π ie 0<= x <=2pi0x2π

x=1.76,4.91x=1.76,4.91