Question

How do I solve for the equation 0 ≤ x < 2π √2 tan x = 2 sin x ?

Answer 1

`x = pi/4, 7/4 pi`

Explanation:

`sqrt(2) tan x = 2 sin`

`tan x / sin x = 2/ sqrt(2)`

`1/cos x = sqrt (2)`

note:
`tan x /sin x = tan x -: sin x = sin x/cos x -: sin x = cancel(sin x)/cos x * 1/ cancel(sin x) = 1/cos x`

`cos x = 1/sqrt (2)`

`x = pi/4, 7/4 pi`