Question

How do i solve: sinx = (cosx)^2 ?

Answer 1

`sin^2(x)+sin(x)-1=0`

Explanation:

Convert `cos(x)^2` to `sin(x)` remember that `1-sin^2(x) = cos^2(x)` and `1-cos^2(x) = sin(x)`

converting the equation gives `Sin(x) = 1-Sin^2(x)`
bring the `sin^2(x)` over to make:
`sin^2(x)+sin(x)=1`

bring the 1 over too...

`sin^2(x)+sin(x)-1=0`
now if my maths is correct, you can solve that as a quadratic