How do I solve this? 5 tan 3x-5=0

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Answer 1 · 2018-02-28T21:19:45

#color(blue)(x=(pi+4pin)/12)#

Not sure of your notation here, I am assuming it is:

#5tan(3x)-5=0#

Add 5 to both sides:

#5tan(3x)=5#

Divide by 5:

#tan(3x)=1#

Taking arctan of both sides:

#3x=arctan(tan(3x))=arctan(1)=>3x=pi/4#

For general solution:

#3x=pi/4+npi#

#x=pi/12+(npi)/3=color(blue)((pi+4pin)/12)#

For any integer #bbn#