Question

How do I solve `(x+1)(x-3)=0 ?`

Answer 1

`x=-1 or x=3`

Explanation:

When the answer is zero, either `x+1=0 or x-3=0`

So, `x=-1 or x=3`

This equation has 2 solutions.

Answer 2

There are two solutions.

`x=-1orx=3`

Explanation:

When any number of factors are multiplied together to give the answer `0`, it means that at least one of the factors must be `0`

if `a xxbxxcxxd xx e =0` it means:

`a=0" "or b=0" "or c=0" "ord=0" "or e=0`

In this case there are two factors:

`color(blue)((x+1))color(red)((x-3))=0`

If `color(blue)((x+1)) =0, rArr" " x=-1`

If`color(red)((x-3))=0, rArr" "x = 3`