How do I solve #(x+1)(x-3)=0 ?#

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Answer 1 · 2018-05-20T06:45:20

#x=-1 or x=3#

When the answer is zero, either #x+1=0 or x-3=0#

So, #x=-1 or x=3#

This equation has 2 solutions.

Answer 2 · 2018-05-20T13:18:44

There are two solutions.

#x=-1orx=3#

When any number of factors are multiplied together to give the answer #0#, it means that at least one of the factors must be #0#

if #a xxbxxcxxd xx e =0# it means:

#a=0" "or b=0" "or c=0" "ord=0" "or e=0#

In this case there are two factors:

#color(blue)((x+1))color(red)((x-3))=0#

If #color(blue)((x+1)) =0, rArr" " x=-1#

If#color(red)((x-3))=0, rArr" "x = 3#