Question

How do i write this as a single logarithim using the properties of logarithims? `log_5 9+log_5 8-1`

Answer 1

`log_x xhArr1` and vice versa.

Explanation:

So we now have:
`=log_5 9+log_5 8 -log_5 5`

We use the properties:
`log(axxb)hArrloga + logb`
`log(a/b)hArrloga - logb`

So:
`=log_5 (9xx8) -log_5 5`

`=log_5 ((9xx8)/5)=log_5 (72/5)=log_5 14.4`