# How do irreducible quadratic denominators complicate partial-fraction decomposition?

##### 1 Answer

If you were trying to find the partial fraction decomposition of

you would break up the denominator into

which would be simplified to be

which is very easily solved.

However, if the problem were

the denominator would factor into

The

When setting up the partial fraction decomposition for something like this, it looks like:

When continuing to solve this, the