# How do resistors add in a parallel circuit?

Jun 28, 2018

$\frac{1}{R} _ t = \frac{1}{R} _ 1 + \frac{1}{R} _ 2 + \frac{1}{R} _ 3 + \ldots$.

#### Explanation:

They add as inverse sums, unlike in a series circuit where they are directly additive..
https://www.swtc.edu/Ag_Power/electrical/lecture/parallel_circuits.htm

Jun 28, 2018

$\frac{1}{R} _ p = \frac{1}{R} _ 1 + \frac{1}{R} _ 2 + \ldots + \frac{1}{R} _ n$