# How do solve the following linear system?: 2x = 4y, 3x+ 2y - 3 = 0 ?

Aug 9, 2018

$x = \frac{3}{4}$ and $y = \frac{3}{8}$

#### Explanation:

From first equation, $x = 2 y$.

Hence,

$3 \cdot 2 y + 2 y - 3 = 0$

$8 y = 3$, so $y = \frac{3}{8}$

Thus,

$x = 2 \cdot \frac{3}{8} = \frac{3}{4}$