How do solve the following linear system?: # 2x + 4y = 8 , 2x-y=4 #?

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Answer 1 · 2016-03-10T16:16:23

The solution for the system of equations is:
#color(green)(x =12 /5 #
#color(green)(y=4/5#

#color(blue)(2x) +4y=8#...........equation #(1)#
#color(blue)(2x)-y=4#..............equation #(2)#

Solving by elimination:
Subtracting equation #(2) # from #(1)# results in elimination of #2x#:

#cancelcolor(blue)(2x) +4y=8#
#-cancelcolor(blue)(2x) +y= -4#

#5y= 4#

#color(green)(y=4/5#

Finding #x# from equation #1#:

#2x +4y=8#

#2x =8 - 4y#

#2x =8 - 4 xx 4/5#

#2x =8 - 16/5#

#2x =40/5 - 16/5#

#2x =24/5 #

#x =cancel24/(5 xx cancel2) #

#color(green)(x =12 /5 #