How do solve the following linear system?: 2x-y=4 , 7x+3y=27 2xy=4,7x+3y=27?

1 Answer
Jun 19, 2018

See a solution process below:

Explanation:

Step 1) Solve the first equation for yy:

2x - y = 42xy=4

2x - color(blue)(4) - y + color(red)(y) = 4 - color(blue)(4) + color(red)(y)2x4y+y=44+y

2x - 4 - 0 = 0 + y2x40=0+y

2x - 4 = y2x4=y

y = 2x - 4y=2x4

Step 2) Substitute (2x - 4)(2x4) for yy in the second equation and solve for xx:

7x + 3y = 277x+3y=27 becomes:

7x + 3(2x - 4) = 277x+3(2x4)=27

7x + (3 xx 2x) - (3 xx 4) = 277x+(3×2x)(3×4)=27

7x + 6x - 12 = 277x+6x12=27

(7 + 6)x - 12 = 27(7+6)x12=27

13x - 12 = 2713x12=27

13x - 12 + color(red)(12) = 27 + color(red)(12)13x12+12=27+12

13x - 0 = 3913x0=39

13x = 3913x=39

(13x)/color(red)(13) = 39/color(red)(13)13x13=3913

(color(red)(cancel(color(black)(13)))x)/cancel(color(red)(13)) = 3

x = 3

Step 3) Substitute 3 for x in the solution to the first equation at the end of Step 1 and calculate y:

y = 2x - 4 becomes:

y = (2 xx 3) - 4

y = 6 - 4

y = 2

The Solution Is:

x = 3 and y = 2

Or

(3, 2)