# How do solve the following linear system?:  3x - 2y = -6 , x/3 + 3y = 9 ?

Jul 5, 2016

x=0, y=3

#### Explanation:

First you can multiply all the terms of the second equation by 3 and then find x:

$\frac{x}{3} + 3 y = 9 \leftrightarrow x + 9 y = 27$

$x = - 9 y + 27$

then you can substitute in x the expression $- 9 y + 27$ in the first equation:

$3 \left(- 9 y + 27\right) - 2 y = - 6$

$- 27 y + 81 - 2 y + 6 = 0$

$- 29 y = - 87$

$y = \frac{87}{29} = 3$

so

$x = - 9 \left(3\right) + 27 = 0$