How do solve the following linear system?: 3x + 4y = -2 , x - 3y = 1 3x+4y=2,x3y=1?

1 Answer
May 25, 2016

x=-2x=2
y=1y=1

Explanation:

3x+4y=-2" (1)"3x+4y=2 (1)
-2x-3y=1" (2)"2x3y=1 (2)

"expand both sides of equation (1) by 2;"expand both sides of equation (1) by 2;
6x+8y=-46x+8y=4
"rearranging the equation :" 6x=-4-8y" "(3)rearranging the equation :6x=48y (3)

"expand both sides of equation 2 by 3;"expand both sides of equation 2 by 3;
-6x-9y=36x9y=3
"rearranging the equation :"6x=-9y-3" "(4)rearranging the equation :6x=9y3 (4)

"Both ;the left sides of equations (3) and (4) are equal" Both ;the left sides of equations (3) and (4) are equal

color(red)(6x)=-4-8y6x=48y
color(red)(6x)=-9y-36x=9y3

"The right sides of equations can be written as equal"The right sides of equations can be written as equal

-4-8y=-9y-348y=9y3

9y-8y=-3+49y8y=3+4

y=1y=1

"now use (1) or (2)"now use (1) or (2)

3x+4*1=-23x+41=2
3x+4=-23x+4=2
3x=-63x=6
x=-6/3x=63
x=-2x=2