How do solve the following linear system?: $4x=-11+y , -x+3y=-5$ ?

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Answer 1 · 2017-09-07T17:37:39

From $-x+3y=-5$ , $x=3y+5$

Hence,

$4*(3y+5)=y-11$

$12y+20=y-11$

$11y=-31$ or $y=-31/11$

Thus, $x=3*(-31/11)+5=-38/11$

1) I found $x$ in terms of $y$ from second equation.

2) I plugged $x$ into first one for findind $y$ .

3) I found $x$ .

How do solve the following linear system?: 4x=-11+y , -x+3y=-5 4x=-11+y , -x+3y=-5 ?