How do solve the following linear system?: # 4x=-11+y , -x+3y=-5 #?

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Answer 1 · 2017-09-07T17:37:39

From #-x+3y=-5#, #x=3y+5#

Hence,

#4*(3y+5)=y-11#

#12y+20=y-11#

#11y=-31# or #y=-31/11#

Thus, #x=3*(-31/11)+5=-38/11#

1) I found #x# in terms of #y# from second equation.

2) I plugged #x# into first one for findind #y#.

3) I found #x#.