How do solve the following linear system?: $4x+21y=6 , 4x-3y=1$ ?

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Answer 1 · 2016-03-23T16:37:29

The solution for the system of equations is:
$color(green)(x =13/32$

$color(green)(y=5/24$

$color(blue)(4x) + 21y = 6$ .........equation $(1)$
$color(blue)(4x) - 3y =1$ ...........equation $(2)$

Solving by elimination:
Subtracting equation $2$ from $1$ :

$cancelcolor(blue)(4x) + 21y = 6$
$-cancelcolor(blue)(4x) + 3y = -1$

$24y = 5$

$color(green)(y=5/24$

Finding $x$ from equation $1$ :

$4x + 21y = 6$

$4x = 6 - 21y$

$4x = 6 - 21 * color(green)(5/24$

$4x = 6 - 105/24$

$4x = 144/24 - 105/24$

$4x =39/24$

$x =39/(24 * 4)$

$color(green)(x =13/32$

How do solve the following linear system?: 4x+21y=6 , 4x-3y=1 4x+21y=6 , 4x-3y=1 ?