How do solve the following linear system?: $4x-2y=2 , x-3y=-2$ ?

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Answer 1 · 2016-10-07T17:36:51

$"solution : x=1 and y=1 "$

$"given :"$

$4x-2y=2" (1)"$

$x-3y=-2" (2)"$

$"expand both side of equation (2) by 4 "$

$4(x-3y)=-2*4$

$4x-12y=-8$

$color(red)(4x)=12y-8" (3)"$
$"rearrange (1)"$

$color(red)(4x)=2y+2" (4)"$

$"(3) and (4) are equal."$

$12y-8=2y+2$

$12y-2y=2+8$

$10y=10$

$y=1$

$"now use (1) or (2)"$

$4x-2*1=2$

$4x-2=2$

$4x=2+2$

$4x=4$

$x=1$

How do solve the following linear system?: 4x-2y=2 , x-3y=-2 4x-2y=2 , x-3y=-2 ?