# How do solve the following linear system?:  4y-16=x , x-2y=8 ?

Dec 29, 2015

Via substitution

#### Explanation:

You have two equations:

$x = 4 y - 16$ & $x - 2 y = 8$

Because $x$ and $y$ are in both equations we can substitute one into the other.

Substitute the first equation into the second:

$\left(4 y - 16\right) - 2 y = 8$

Now group your $y$ terms:

$- 16 + 2 y = 8$

Now solve for $y$:

$2 y = 24$ $\to$ $y = \frac{24}{2}$ $\to$ $y = \ldots$ You do the rest!

Don't forget to substitute your answer into the original equations to check it is correct.