# How do solve the following linear system?: # 6x=29-8y , 3y = 1 -x #?

##### 2 Answers

The solution is a point at

#### Explanation:

Substitution implies that we solve for either

Then we substitute

Then we can use our original solution for

**check:**

*eq1:*

*eq2:*

#### Explanation:

**Given:**

Write the equations separately:

**Equation (1)**

**Equation (2)**

Consider

**Equation (1)**

Add

**Equation (3)**

Consider

**Equation (2)**

Add

**Equation (4)**

Consider:

**Equation (3)**

**Equation (4)**

Multiply both sides of the **Equation (4)** by 6.

This resultant equation is **Equation (5)**

**Equation (3)**

**Equation (5)**

Subtract **Equation (5)** from **Equation (3)**

**Equation (3)**

**Equation (5)**

You get

Divide both sides by 10 to get

Multiply both sides by

Substitute this value of **Equation (4)** to get

Add

Take the common denominator of the numeric expression at the Right-Hand Side(RHS) to simplify:

Hence, values of

The system of linear equations is solved.