How do solve the following linear system?: $-6x+5y=1 , 5x-5y=10$ ?

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Answer 1 · 2018-05-14T20:09:14

$(-11,-13)$

Since you have $+5y$ in one equation and $-5y$ in the other equation, you can add both equations to cancel out the y terms and solve for x.

$-6x + 5x=-x$
$5y-5y=0$
$1+10=11$
therefore
$-x=11$
multiplying both sides by -1:
$x = -11$

plugging this back into the first equation:

$-6(-11)+5y=1$
$66+5y=1$
subtracting 66 from both sides:
$5y=-65$
divide both sides by 5:
$y=-13$

putting the x-values and y-values into one point gives:
$(-11,-13)$
as the solution

How do solve the following linear system?: -6x+5y=1 , 5x-5y=10 -6x+5y=1 , 5x-5y=10 ?