# How do solve the following linear system?:  -9x + 6y = -2 , 4x-2y=-2 ?

Dec 7, 2015

$x = - \frac{8}{3} \mathmr{and} y = - \frac{13}{3}$

#### Explanation:

$- 9 x + 6 y = - 2$ (Consider this as equation 1)
$4 x - 2 y = - 2$ (Consider this as equation 2)

$x = \frac{2 + 6 y}{9}$ (From equation 1)
Substitute this in equation 2
$4 \left(\frac{2 + 6 y}{9}\right) - 2 y = - 2$
$8 + 24 y - 18 y = - 18$
$8 + 6 y = - 18$
$6 y = - 26$
$y = - \frac{26}{6} = - \frac{13}{3}$

Substitute this in equation 1
$- 9 x + 6 \left(- \frac{26}{6}\right) = - 2$
$- 9 x - 26 = - 2$
$x = - \frac{24}{9} = - \frac{8}{3}$