How do solve the following linear system?: # x+2y =2 , x-2y = -3 #?

1 Answer
Dec 28, 2015

Answer:

Step by step:

Explanation:

First, we need to isolate one variable. The easiest, in this case, is x. #x + 2y =2# becomes #x = 2 -2y#. We now have X's value and need to find Y's value.
Second, we change X in the second equation to its new value: #x - 2y=-3# becomes #2 -2y -2y = -3#.
Solving the new equation: #2 - 4y = -3#, then we pass the 2 to the other side of the equation: #-4y = -3 - 2 = -5# and #-4y = -5#, so #y = (-5)/(-4) = 5/4#.
With the exact value of Y, we now go back to the first equation: #x = 2 - 2y = 2 - 10/4 = 8/4 - 10/4 = -2/4 ", so, " x = -2/4 " or " -0,5#