# How do solve the following linear system?:  x+2y =2 , x-2y = -3 ?

First, we need to isolate one variable. The easiest, in this case, is x. $x + 2 y = 2$ becomes $x = 2 - 2 y$. We now have X's value and need to find Y's value.
Second, we change X in the second equation to its new value: $x - 2 y = - 3$ becomes $2 - 2 y - 2 y = - 3$.
Solving the new equation: $2 - 4 y = - 3$, then we pass the 2 to the other side of the equation: $- 4 y = - 3 - 2 = - 5$ and $- 4 y = - 5$, so $y = \frac{- 5}{- 4} = \frac{5}{4}$.
With the exact value of Y, we now go back to the first equation: $x = 2 - 2 y = 2 - \frac{10}{4} = \frac{8}{4} - \frac{10}{4} = - \frac{2}{4} \text{, so, " x = -2/4 " or } - 0 , 5$