# How do solve the following linear system?:  x-2y=8 , 4x=-11+y ?

Jan 3, 2016

I found:
$x = - \frac{30}{7}$
$y = - \frac{43}{7}$

#### Explanation:

We can isolate $x$ from the first equation and substitute into the second to find $y$:
$x = 8 + 2 y$
So:
$4 \left(8 + 2 y\right) = - 11 + y$
$32 + 8 y = - 11 + y$
$7 y = - 43$
$y = - \frac{43}{7}$
We use this value back into the first equation:
$x = 8 + 2 \left(- \frac{43}{7}\right) = \frac{56 - 86}{7} = - \frac{30}{7}$