# How do solve the following linear system?:  x - 3y = 8 , y = 8 x - 3 ?

Apr 28, 2016

$x = \frac{1}{23}$ and $y = - 2 \frac{15}{23}$.

#### Explanation:

One method is to to replace $y$ in the first equation by $\left(8 x - 3\right)$. You can do this because you are told that $y$ has the same value as $8 x - 3$.

This means they are interchangeable. Substituting for $y$ will lead to a linear equation with only one variable, which means you can solve it for $x$.

$x - 3 \left(8 x - 3\right) = 8$

$x = \frac{1}{23}$

Then use this value for $x$ in the equation $y = 8 x - 3$ to solve for $y$. You should get the answers given.