How do solve the following linear system?: # x+4y=3 , 6x=29-8y #?

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Answer 1 · 2016-01-07T17:06:39

The solution for the system of equations is

#color(blue)(x=23/4 , y=-11/16#

#x+4y=3#, multiplying by #6#
#color(blue)(6x)+24y=18#.....equation #(1)#

#6x=29-8y#

#6x+8y=29#.......equation #(2)#

Solving by elimination.
Subtracting equation #2# from #1#

#cancelcolor(blue)(6x)+24y=18#
#-cancelcolor(blue)(6x)-8y=-29#

#16y=-11#

#color(blue)(y=(-11)/16#

Finding #x# from equation #1#
#x+4y=3#

#x=3-4y#
#x=3-4 xx(-11/16)#

#x=3+(44/16)#

#x=48/16+(44/16)#

#x=(92/16)#

#color(blue)(x=23/4#