How do solve the following linear system?: $x = y - 11, - 8 x + y = 2$ $x= y - 11 , -8x + y = 2$ ?

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How do solve the following linear system?: $x = y - 11, - 8 x + y = 2$ $x= y - 11 , -8x + y = 2$ ?

1 Answer

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Answer 1 · 2016-01-22T00:39:16

I found:
$x = \frac{9}{7}$ $x=9/7$
$y = \frac{86}{7}$ $y=86/7$

Explanation:

Let us take the first equation and substitute into the second for $x$ $x$ :
$- 8 (y - 11) + y = 2$ $-8(color(red)(y-11))+y=2$
solve for $y$ $y$ :
$- 8 y + 88 + y = 2$ $-8y+88+y=2$
$7 y = 86$ $7y=86$
so $y = \frac{86}{7}$ $y=86/7$
substitute this back into the first equation:
$x = \frac{86}{7} - 11 = \frac{9}{7}$ $x=86/7-11=9/7$

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How do solve the following linear system?: $x = y - 11, - 8 x + y = 2$ $x= y - 11 , -8x + y = 2$ ?

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

How do solve the following linear system?: x= y - 11 , -8x + y = 2 x=y−11,−8x+y=2 x= y - 11 , -8x + y = 2 ?

1 Answer

Explanation:

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Impact of this question

How do solve the following linear system?: $x = y - 11, - 8 x + y = 2$ $x= y - 11 , -8x + y = 2$ ?