How do solve the following linear system?: $x + y = 12, 3 x + 4 y = - 2$ $x + y= 12 , 3x + 4y = -2$ ?

Question

1290 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-09T05:14:17

$x = 50, y = - 38$ $color(green)(x = 50, y = -38$

$x + y = 12, Eqn (1)$ $x + y = 12, " Eqn (1)"$

$3 x + 4 y = - 2, Eqn (2)$ $3x + 4y = -2, " Eqn (2)"$

$Eqn ( 2) - 3 * Eqn (1) gives$ $" Eqn ( 2) - 3 * Eqn (1) gives "$

$3 x + 4 y - 3 x - 3 y = - 2 - 36$ $3x + 4y -3x -3y = -2 - 36$

$y = - 38$ $color(green)(y = -38$

Substituting value of y in Eqn (1),

$x = 12 + 38 = 50$ $color(green)(x = 12 + 38 = 50$

How do solve the following linear system?: x+y=12,3x+4y=−2 x + y= 12 , 3x + 4y = -2 ?