How do solve the following linear system?: $y = 8 x - 3 , 3y = 15 -6x$ ?

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Answer 1 · 2018-06-10T06:22:33

$x=0.6,y=3.8$

Multiply the first equation by 3

$3y=24x-9$

Subtract the second equation

$0=30x-18$

Add 18

$30x=18$

Divide by 30

$x=3/5$

Substitute this answer into $3y=15-6x$

$3y=15-18/5$

$3y=57/5$

Divide by 3

$y=19/5$

How do solve the following linear system?: y = 8 x - 3 , 3y = 15 -6x y = 8 x - 3 , 3y = 15 -6x ?