How do solve the following linear system?:  y = 8 x - 3 , 3y = 15 -6x ?

Jun 10, 2018

$x = 0.6 , y = 3.8$

Explanation:

Multiply the first equation by 3

$3 y = 24 x - 9$

Subtract the second equation

$0 = 30 x - 18$

$30 x = 18$

Divide by 30

$x = \frac{3}{5}$

Substitute this answer into $3 y = 15 - 6 x$

$3 y = 15 - \frac{18}{5}$

$3 y = \frac{57}{5}$

Divide by 3

$y = \frac{19}{5}$