How do you add #3x ( 6x - 1) + 2( 2x - 3) #?

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Answer 1 · 2017-07-20T14:12:26

See a solution process below:

First, expand the terms in parenthesis by multiplying each of the terms within a parenthesis by the term outside the parenthesis:

#color(red)(3x)(6x - 1) + color(blue)(2)(2x - 3) =>#

#(color(red)(3x) * 6x) - (color(red)(3x) * 1) + (color(blue)(2) * 2x) - (color(blue)(2) * 3) =>#

#18x^2 - 3x + 4x - 6#

Now, combine like terms:

#18x^2 + (-3 + 4)x - 6 =>#

#18x^2 + 1x - 6 =>#

#18x^2 + x - 6#