How do you add #4x ^ { 2} \sqrt { ( 6x ^ { 8} ) } + 3\sqrt { ( 6x ^ { 12} ) }#?

1 Answer
Tazwar Sikder
Jun 11, 2017

#7 sqrt(6) x^(6)#

Explanation:

We have: #4 x^(2) sqrt((6 x^(8))) + 3 sqrt((6 x^(12)))#

#= 4 x^(2) cdot sqrt(6) cdot x^(frac(8)(2)) + 3 cdot sqrt(6) cdot x^(frac(12)(2))#

#= 4 sqrt(6) x^(2) cdot x^(4) + 3 sqrt(6) x^(6)#

#= 4 sqrt(6) x^(6) + 3 sqrt(6) x^(6)#

#= 7 sqrt(6) x^(6)#

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