How do you add #5\sqrt { 2y } + 7\sqrt { 2y }#?

2 Answers
Jan 26, 2018

#12sqrt(2y)#

Explanation:

You can treat #sqrt(2y)# as a variable and just add the coefficients.

#5sqrt(2y) + 7sqrt(2y) = 12sqrt(2y)#

Jan 26, 2018

#=12 sqrt(2y)#

Explanation:

Let #sqrt(2y) = a#

Then the given term becomes,

#5 a + 7 a= 12 a#

Now replace a with #sqrt(2y)#

It becomes #12 sqrt(2y)#