How do you add #5\sqrt { 2y } + 7\sqrt { 2y }#?

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Answer 1 · 2018-01-26T08:18:15

#12sqrt(2y)#

You can treat #sqrt(2y)# as a variable and just add the coefficients.

#5sqrt(2y) + 7sqrt(2y) = 12sqrt(2y)#

Answer 2 · 2018-01-26T08:31:30

#=12 sqrt(2y)#

Let #sqrt(2y) = a#

Then the given term becomes,

#5 a + 7 a= 12 a#

Now replace a with #sqrt(2y)#

It becomes #12 sqrt(2y)#