How do you add and subtract the radicals #3sqrt(5/12) + sqrt(12/5) -1/3sqrt60#?

1 Answer

Answer:

#7/{2\sqrt15}#

Explanation:

Given that

#3\sqrt{5/12}+\sqrt{12/5}-1/3\sqrt{60}#

#=3\sqrt{5}/{\sqrt12}+\sqrt{12}/{\sqrt5}-1/3\sqrt{60}#

#={3\cdot 3(\sqrt5\sqrt5)+3(\sqrt12\sqrt12)-(\sqrt60\sqrt60)}/{3\sqrt{60}}#

#={9(5)+3(12)-(60)}/{3\sqrt{60}}#

#={45+36-60}/{3\sqrt{60}}#

#=21/{3\sqrt60}#

#=7/{2\sqrt15}#