Question

How do you add `\frac { 1} { 3x ^ { 2} - 8x + 5} + \frac { 2} { 3x ^ { 2} - 14x + 15}`?

Answer 1

`1/[(x^2-4x+3)`

Explanation:

`1/(3x^2-8+5)+2/(3x^2-14x+15)`

=`1/[(3x-5)(x-1)]+2/[(3x-5)(x-3)]`

=`[1*(x-3)+2*(x-1)]/[(3x-5)(x-1)(x-3)]`

=`(3x-5)/[(3x-5)(x-1)(x-3)]`

=`1/[(x-1)*(x-3)]`

=`1/[(x^2-4x+3)`