Question

How do you add `\frac { - 1} { 8d } + \frac { 7} { 6d }`?

Answer 1

See the solution process below:

Explanation:

To add two fractions they must be over a common denominator. For this problem the Lowest Common Denominator is `24d`. Therefore, before adding we must multiply each fraction by the appropriate form of `1` to put them each over this common denominator:

`(3/3 xx -1/(8d)) + (4/4 xx 7/(6d)) => ((3 xx -1)/(3 xx 8d)) + ((4 xx 7)/(4 xx 6d))`

`=> -3/(24d) + 28/(24d)`

We can now add the numerators over the common denominators:

`-3/(24d) + 28/(24d) => (-3 + 28)/(24d) => 25/(24d)`