How do you add $\frac{3x-2}{x-2}+\frac{1}{x^2-4x+4}$ ?

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Answer 1 · 2014-12-11T06:38:03

${3x-2}/{x-2}+1/{x^2-4x+4}$

by factoring out the denominator of the second quotient,

$={3x-2}/{x-2}+1/{(x-2)^2}$

by multiplying the numerator and the denominator of the first quotient by $(x-2)$ ,

$={3x^2-8x+4}/{(x-2)^2}+1/{(x-2)^2}$

by combining the two quotients together,

$={3x^2-8x+5}/{(x-2)^2}$

by factoring out the numerator,

$={(3x-5)(x-1)}/{(x-2)^2}$

I hope that this was helpful.

How do you add \frac{3x-2}{x-2}+\frac{1}{x^2-4x+4}\frac{3x-2}{x-2}+\frac{1}{x^2-4x+4}?