How do you add #\frac { 7a } { 4q + 8} + \frac { q } { 12q + 24}#?

Question

737 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-08T04:03:59

#(7a)/(4q+8)+q/(12q+24)=(21a+q)/(12(q+2))#

#(7a)/(4q+8)+q/(12q+24)#

First, factor both denominators.

#(7a)/(4(q+2))+q/(12(q+2))#

Now multiply the first term by #3/3#.

#(7a)/(4(q+2))*3/3+q/(12(q+2))=(21a)/(12(q+2))+q/(12(q+2))#

Common denominators now allow us to add the numerators.

#(21a+q)/(12(q+2))#