# How do you add sqrt 18 + 2 sqrt 75 - sqrt 48?

$\sqrt{6 \cdot 3} + 2 \sqrt{25 \cdot 3} - \sqrt{6 \cdot 8} =$
$= \sqrt{6} \sqrt{3} + \sqrt{4 \cdot 25 \cdot 3} - \sqrt{6} \sqrt{4 \cdot 2} =$
$= \sqrt{6} \sqrt{3} + \sqrt{25 \cdot 12} - \sqrt{6} \sqrt{4 \cdot 2} =$
$= \sqrt{6} \sqrt{3} + 5 \sqrt{6} \sqrt{2} - 2 \sqrt{6} \sqrt{2} =$
$= \sqrt{6} \left[\sqrt{3} + 5 \sqrt{2} - 2 \sqrt{2}\right] =$
$= \sqrt{6} \left[\sqrt{3} + 3 \sqrt{2}\right] =$