How do you add #sqrt 18 + 2 sqrt 75 - sqrt 48#?

1 Answer
Apr 17, 2015

I would write it as:
#sqrt(6*3)+2sqrt(25*3)-sqrt(6*8)=#
#=sqrt(6)sqrt(3)+sqrt(4*25*3)-sqrt(6)sqrt(4*2)=#
#=sqrt(6)sqrt(3)+sqrt(25*12)-sqrt(6)sqrt(4*2)=#
#=sqrt(6)sqrt(3)+5sqrt(6)sqrt(2)-2sqrt(6)sqrt(2)=#
#=sqrt(6)[sqrt(3)+5sqrt(2)-2sqrt(2)]=#
#=sqrt(6)[sqrt(3)+3sqrt(2)]=#