How do you add #sqrt12+sqrt75#?

1 Answer
Oct 6, 2015

Answer:

If you take the number apart (factorize) you'll see that:
#12=2*2*3and75=3*5*5#

Explanation:

You can take the 'doubles' (squares) out from under the root, where they become single:

#sqrt12=sqrt(2*2*3)=sqrt(2^2)*sqrt3=2sqrt3#

#sqrt75=sqrt(5*5*3)=sqrt(5^2)*sqrt3=5sqrt3#

Adding these will give you #7sqrt3# as the final answer.