# How do you add square root of 2 plus the square root of 6?

Oct 8, 2015

$\sqrt{2} \cdot \left(1 + \sqrt{3}\right)$

#### Explanation:

Your starting expression looks like this

$\sqrt{2} + \sqrt{6}$

Now, because the square root terms are different, you can't really add these two radicals. However, you could simplify this expression a bit.

Notice that you can write $6$ as

$6 = 2 \cdot 3$

This means that you have

$\sqrt{2} + \sqrt{2 \cdot 3} = \sqrt{2} + \sqrt{2} \cdot \sqrt{3}$

Now use $\sqrt{2}$ as a common factor to get

sqrt(2) + sqrt(2) * sqrt(3) = color(green)(sqrt(2) * (1 + sqrt(3))