How do you algebraically show if #(-4,1)# is on the line #y=-5/4x-2#?

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Answer 1 · 2016-12-06T20:46:13

#(-4, 1)# does not lie on the given line.

#(-4,1)# represent #x and y# values .

Substitute the #x-# value into the equation and check whether that makes the equation true.

#y = -5/4x-2#

#y= -5/4(-4) -2#

#y = 5-2#

#y=3#

This is not equal to the given y-value of 1 which means the point
#(-4,1)# does not lie on the given line.