How do you approximate $log_5 0.5$ given $log_5 2=0.4307$ and $log_5 3=0.6826$ ?

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Answer 1 · 2016-10-19T03:55:31

$log_5(0.5)~~-0.4307$

We will use the following:

With that:

$log_5(0.5) = log_5(1/2)$

$=log_5(2^(-1))$

$=-1*log_5(2)$

$=-log_5(2)$

$~~-0.4307$

How do you approximate log_5 0.5log_5 0.5 given log_5 2=0.4307log_5 2=0.4307 and log_5 3=0.6826log_5 3=0.6826?