How do you approximate #log_5 30# given #log_5 2=0.4307# and #log_5 3=0.6826#?
1 Answer
Nov 29, 2016
Rewrite
#log_5(30)=log_5(2*3*5)#
Using the rule
#log_5(30)=log_5(2)+log_5(3)+log_5(5)#
Using
#log_5(30)approx0.4307+0.6826+1approx2.1133#