# How do you balance SO2+O2+H2O=H2SO4?

Mar 5, 2017

$2 S {O}_{2} + {O}_{2} + 2 {H}_{2} O \to 2 {H}_{2} S {O}_{4}$

#### Explanation:

$S {O}_{2} + {O}_{2} + {H}_{2} O \to {H}_{2} S {O}_{4}$

Atoms on the left: $1 - S , 5 - O , 2 - H$
Atoms on the right: $1 - S , 4 - O , 2 - H$

To make the number of oxygen on the left to be even, add $2$ molecules to ${H}_{2} O$ and a $2$ to the right.

$S {O}_{2} + {O}_{2} + 2 {H}_{2} O \to 2 {H}_{2} S {O}_{4}$

Atoms on the left: $1 - S , 6 - O , 4 - H$
Atoms on the right: $2 - S , 8 - O , 4 - H$

To make the number of $S$ to be the same, add $2$ molecules to the $S {O}_{2}$ on the left:

$2 S {O}_{2} + {O}_{2} + 2 {H}_{2} O \to 2 {H}_{2} S {O}_{4}$

Atoms on the left: $2 - S , 8 - O , 4 - H$
Atoms on the right: $2 - S , 8 - O , 4 - H$

Balanced!