How do you calculate #(6.3times10^3) div (2.5times10^8)#?

1 Answer
Oct 4, 2016

#2.52 xx 10^-5 #

Explanation:

Consider #(12 xx x^3)/(8xx x^8)#

simplify the numbers #rarr 3/2 xx x^-5 larr# subtract the indices

Do exactly the same with #(6.3xx10^3)/(2.5 xx10^8)#

simplify the numbers #rarr 2.52 xx 10^-5 larr# subtract the indices.

Note: usually we would not leave an answer with a negative indexm but as we are dealing with scientific notation, in this case we do.