How do you calculate #8^(2/log 2) #?

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Answer 1 · 2018-07-17T19:46:29

#8^{2/{\log 2}}=10^6#

Given that

#8^{2/{\log 2}}#

#=(2^3)^{2/{\log 2}}#

#=2^{6/{\log 2}}#

#=2^{6\log_2(10)}#

#=2^{\log_2(10^6)}#

#=10^6#